Integration — AS & A Level Mathematics (9709) questions by topic

Evaluating a definite integral of a rational function to reach a logarithmic answer, finding the area under a curve involving fractional powers of x between two roots, and using integration to find an unknown constant from a given definite-integral value are typical of the 33 integration questions from 2023 to 2025, worth 3 to 12 marks.

Find, show, determine, use and deduce lead the command words, each demanding a fully shown antiderivative and substitution of limits rather than a calculator-only final value. Because a missing negative sign or a wrong limit substitution is the most common way marks are lost here, submit your integration working for instant marking, so any such slip is caught at the exact line it occurs.

May–June 2025, Paper 11

Question 4 · 5 marks

The diagram shows the curve with equation y = 5x^(3/2) − 20x and the line with equation y = x − 16. The x-coordinates of the points of intersection of the curve and line are 1 and…

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May–June 2025, Paper 12

Question 6 · 6 marks

The diagram shows the curve with equation y = 9 / (5x + 4)^(1/2) and the line y = 6 − 3x. The line and the curve intersect at the point P which has y-coordinate 3. The shaded…

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Question 9 · 12 marks

The equation of a curve is such that d^2y/dx^2 = −24/x^3. It is given that the curve has a stationary point at (−2, 19). Find an expression for dy/dx.

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May–June 2025, Paper 13

Question 3 · 4 marks

Given that the integral from 1 to 3 of ( a/((4x − 3)^2) + 2 ) dx = 12, find the value of the constant a.

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May–June 2025, Paper 15

Question 1 · 4 marks

The equation of a curve is such that dy/dx = 12(2x − 5)^2 + 8x. It is given that the curve passes through the point (2, 4). Find an equation of the curve. [4]

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Question 4 · 5 marks

The diagram shows part of the curve y = x^2 − 1/x^2. The shaded region is bounded by the curve, the line x = 2 and the x-axis. Find the volume formed when the shaded region is…

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May–June 2025, Paper 22

Question 1 · 3 marks

Show that integral from 2 to 11 of 8/(4x + 1) dx = ln a, where a is an integer to be found.

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May–June 2025, Paper 23

Question 1 · 3 marks

Show that integral from 2 to 11 of 8/(4x + 1) dx = ln a, where a is an integer to be found.

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May–June 2025, Paper 25

Question 1 · 3 marks

Show that integral from 2 to 11 of 8/(4x + 1) dx = ln a, where a is an integer to be found.

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May–June 2025, Paper 31

Question 9 · 10 marks

The constant a is such that ∫ from 1 to a of 6x ln x dx = 4. Show that a = exp((1/6)(5/a² + 3)), where exp(x) denotes e^x.

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May–June 2025, Paper 33

Question 3 · 4 marks

Find the exact value of the integral from (1/5)π to (1/4)π of 3 cos²(5x) dx, i.e. ∫{(1/5)π}^{(1/4)π} 3 cos²(5x) dx.

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May–June 2024, Paper 13

Question 6 · 7 marks

A curve passes through the point (4/5, −3) and is such that dy/dx = −20/(5x − 3)^2. Find the equation of the curve.

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May–June 2024, Paper 21

Question 6 · 9 marks

The diagram shows the curve with equation y = √(sin 2x + sin² 2x) for 0 ≤ x ≤ (1/6)π. The shaded region is bounded by the curve and the straight lines x = (1/6)π and y = 0. Use…

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May–June 2024, Paper 31

Question 8 · 7 marks

Use the substitution u = 1 − sin x to find the exact value of ∫ from π to (3/2)π of (sin 2x) / √(1 − sin x) dx. Give your answer in the form a + b√2, where a and b are rational…

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October–November 2024, Paper 21

Question 5 · 8 marks

It is given that ∫ₐ^(a³) 10/(2x + 1) dx = 7, where a is a constant greater than 1. Show that a = ∛(0.5 e^(1.4)(2a + 1) − 0.5). [5]

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October–November 2024, Paper 22

Question 6 · 9 marks

The diagram shows the curves with equations y = ∛(5x² + 7) and y = 27/(2x + 5) for x ≥ 0. The curves meet at the point (2, 3). Region A is bounded by the curve y = ∛(5x² + 7) and…

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October–November 2024, Paper 23

Question 5 · 8 marks

It is given that ∫ from a to a³ of 10/(2x + 1) dx = 7, where a is a constant greater than 1. Show that a = ³√(0.5 e^(1.4) (2a + 1) − 0.5).

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October–November 2024, Paper 31

Question 2 · 5 marks

Find the exact value of ∫₁³ x² ln 3x dx. Give your answer in the form a ln b + c, where a and c are rational and b is an integer.

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May–June 2023, Paper 11

Question 10 · 11 marks

The diagram shows part of the curve y = 4/(2x − 1)² and parts of the lines x = 1 and y = 1; the curve passes through A(1, 4) and B(3/2, 1), and the shaded region is bounded by the…

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May–June 2023, Paper 12

Question 1 · 3 marks

The equation of a curve is such that dy/dx = 4/(x − 3)³ for x 3. The curve passes through the point (4, 5). Find the equation of the curve.

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Question 5 · 4 marks

The diagram shows the curve with equation y = 10x^(1/2) − (5/2)x^(3/2) for x 0. The curve meets the x-axis at the points (0, 0) and (4, 0). Find the area of the shaded region.

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May–June 2023, Paper 13

Question 9 · 10 marks

A curve which passes through (0, 3) has equation y = f(x). It is given that f′(x) = 1 − 2/(x − 1)³. Find the equation of the curve.

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May–June 2023, Paper 21

Question 3 · 7 marks

It is given that ∫₀ᵃ (3e^(2x) − 1) dx = 12, where a is a positive constant. Show that a = (1/2) ln(9 + (2/3)a). [4]

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Question 6 · 7 marks

Show that ∫ from (1/4)π to (1/3)π of (4 cos^2 2x + 1/cos^2 x) dx = (3/4)√3 + (1/6)π − 1. [7]

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May–June 2023, Paper 22

Question 3 · 5 marks

The diagram shows part of the curve y = 6/(2x + 3). The shaded region is bounded by the curve and the lines x = 6 and y = 2. Find the exact area of the shaded region, giving your…

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May–June 2023, Paper 23

Question 3 · 5 marks

The diagram shows part of the curve y = 6 / (2x + 3). The shaded region is bounded by the curve and the lines x = 6 and y = 2. Find the exact area of the shaded region, giving…

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May–June 2023, Paper 31

Question 9 · 10 marks

The constant a is such that ∫₀ᵃ x e^(−2x) dx = 1/8. Show that a = ½ ln(4a + 2).

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May–June 2023, Paper 33

Question 7 · 8 marks

Use the substitution u = cos x to show that ∫₀^π sin 2x e^(2 cos x) dx = ∫₋₁¹ 2u e^(2u) du.

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October–November 2023, Paper 11

Question 10 · 11 marks

A curve has a stationary point at (2, −10) and is such that d²y/dx² = 6x. Find dy/dx.

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October–November 2023, Paper 13

Question 1 · 4 marks

A curve is such that its gradient at a point (x, y) is given by dy/dx = x − 3x^(−1/2). It is given that the curve passes through the point (4, 1). Find the equation of the curve.

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October–November 2023, Paper 21

Question 3 · 6 marks

Find ∫₄¹⁰ 4/(2x − 5) dx, giving your answer in the form ln a, where a is an integer. [4]

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October–November 2023, Paper 23

Question 3 · 6 marks

Find ∫₄¹⁰ 4/(2x − 5) dx, giving your answer in the form ln a, where a is an integer.

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October–November 2023, Paper 32

Question 5 · 6 marks

Find the exact value of ∫₀⁶ [x(x + 1) / (x² + 4)] dx.

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