AS & A Level Mathematics (9709) — May–June 2025, Paper 33

11 questions · every question answerable online with instant point-by-point AI marking against the official mark scheme.

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Question 1 · 4 marks · Algebra (modulus functions)

Sketch the graph of y = 3x − 2a , where a is a positive constant.

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Question 2 · 4 marks · Logarithmic and exponential functions

Solve the equation 2 ln(2x + 3) − ln(2x + 5) = ln(3x).

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Question 3 · 4 marks · Integration (using double angle formulae)

Find the exact value of the integral from (1/5)π to (1/4)π of 3 cos²(5x) dx, i.e. ∫{(1/5)π}^{(1/4)π} 3 cos²(5x) dx.

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Question 4 · 6 marks · Complex numbers (exponential/polar form, conjugates)

It is given that z1 = r1 e^(iθ1) and z2 = r2 e^(iθ2). Show that (z1 z2) = z1 z2.

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Question 5 · 6 marks · Differentiation (implicit differentiation)

The equation of a curve is xy + y² e^(−x) = 4. Show that dy/dx = (y² − y e^x) / (x e^x + 2y).

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Question 6 · 6 marks · Complex numbers (Cartesian form, modulus, real part)

Find the complex numbers z for which (z + 4)/(z + 4i) is real and z = √10. Give your answers in the form z = x + iy, where x and y are real.

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Question 7 · 8 marks · Algebra (partial fractions)

Let f(x) = (3a − 5x) / ((3a + 2x)(2a − x)), where a is a positive constant. Express f(x) in partial fractions.

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Question 8 · 8 marks · Trigonometry (identities, double angle formulae)

Prove the identity cot²θ − tan²θ ≡ 4 cot 2θ cosec 2θ.

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Question 9 · 8 marks · Vectors (equation of a line)

With respect to the origin O, the points A, B and C have position vectors given by OA = i + 2j, OB = i + 3j − 2k, and OC = 2i − j + 3k. The line l passes through B and C. Find a…

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Question 10 · 10 marks · Differential equations (separation of variables, integration by parts)

The variables x and y satisfy the differential equation sin 4y (dy/dx) = x sin 2y sin 3x. It is given that y = (1/12)π when x = (1/2)π. Solve the differential equation, obtaining…

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Question 11 · 11 marks · Differentiation (product rule, stationary points)

The diagram shows the curve y = √x sin 2x for 0 ⩽ x ⩽ (1/2)π. The curve has a maximum point at M, where x = a. Show that tan 2a = −4a.

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← May–June 2025 Paper 35 · May–June 2025 Paper 32 →

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